Two men A and B started a job in which A was thrice as good as B and therefore took 60 days less than B to finish the job. How many days will they take to finish the job, if they start working together?
A B Efficiency 3 : 1 Time 1 : 3 Difference in time = 60 days ⇒ 3x - x = 60 ⇒ x = 30 days So, Total Work = 30 × 3 = 90 A and B can do work together in days = 90/4 = 22.5 days ∴ The required answer is 22.5 days.
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