Question
βAβ and βBβ can do a piece of work in 15 days
and 18 days, respectively. They started working together but βAβ left after 5 days. Find the time taken by βBβ to complete the remaining work.Solution
Let total amount of work be 90 units (LCM of 15 and 18). Efficiency of βAβ = 90/15 = 6 units/day Efficiency of βBβ = 90/18 = 5 units/day Amount of work done by βAβ and βBβ together in 5 days = (6 + 5) Γ 5 = 55 units Time taken by B to complete remaining work = {(90 β 55)/5} = 7 days
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