Question
A, B, and C together can do a work alone in 9 days, 45
days, and 90 days respectively. A alone starts the work and work for 3 days and leaves the work, then B alone does the work for 8 days and leaves the work. If remaining work is done by C alone then for how many days has C worked?Solution
Total work = LCM of 9, 45 and 90 = 90 units Unit per day of A = 90/9 = 10 Unit per day of B = 90/45 = 2 Unit per day of C = 90/90 = 1 Units of work done by A in 3 days = 10 × 3 = 30 units Units of work done by B in 8 days = 8 × 2 = 16 units Remaining work = 90 – (30 + 16) = 44 units So, C has worked for 44/1 = 44 days
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