Question
A can finish a task in 32 days, while B can complete the
same task 8 days sooner than A. If they together earn a total of Rs. 1050 for the job, how much does A receive?Solution
Time taken by βAβ to complete the work = 32 days Time taken by βBβ to complete the work = 32 β 8 = 24 days Ratio of efficiencies is inverse of number of days taken Therefore, ratio of efficiencies of βAβ to βBβ = 24:32 = 3:4 Wage received by βAβ = 1050 Γ (3/7) = Rs. 450Β
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (β 484 β β 256) = ?
(13)2Β - 3127 Γ· 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 Γ· 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 Γ 5 - {272 + 162 - 422}
(15 Γ 225) Γ· (45 Γ 5) + 480 = ? + 25% of 1240
β [? x 11 + (β 1296)] = 16
11 Γ 25 + 12 Γ 15 + 14 Γ 20 + 15 = ?