Question
Ram can do a piece of work in 12 days and Shyam can do
the same work in 16 days. They both started work together, Ram left 2 days before the completion of work. Then the total work is completed in how many days?Solution
Required Answer = [((16-2) ×12 )/(12+16) ] + 2 = (14 × 12)/28 + 2 = 8 days Alternate method: Ram can do a job in 12 days & Shyam can do same job in 16 days. Let assume total work = LCM (12, 16) = 48 units So Ram can daily do = 48 / 12= 4 units & Shyam can do daily = 48/ 16 = 3 units So Ram left 2 days before the completion of work ,it means that Shyam worked alone in last 2 days Hence Shyam did in last 2 days = 3× 2 = 6 units So remaining work = 48 – 6 = 42 is done by both Hence they worked together initially for = 42/(4 + 3) = 42 / 7 = 6 days Hence total days for completing the work = 6 days + 2 days = 8 days
107    157    194    ?     237    247
...32, 48, 72, 108, ?, 243
9    14    38    129    ?   2705   16260
...Find the missing number in the given number series.
?, 26, 38, 70, 130, 226
Find the missing number in the given number series.
2, 5, 11, 23, 47, ?What will come in place of (?) Question mark in the given number series.
28, 29, 38, 63, 112, 193, ?
114, 115, 118, 127, ?, 235
What will come in place of the question mark (?) in the following series?
100, 81, 64, 51, 40, ?
What will come in place of (?) question mark in the given number series.
52, 61, 79, 106, 142, ?Â
58, 63, 78, ?, 138, 183