Total work = Number of days×1 day’s work (efficiency) Total work = LCM (6, 8, 4) = 24 unit 1 day’s work of (A+B) = 24/6 = 4 unit 1 day’s work of (B + C) = 24/8 = 3 unit 1 day’s work of (A + B + C) = 24/4 = 6 unit Now, 1 day’s work of A = 6 – 3 = 3 1 day’s work of C = 6 – 4 = 2 1 day’s work of A and C = 3 + 2 = 5 A and C together can complete the job in = 24/5 = 4.8 days
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