Question
A and B together can do a work in 10 days, B and C can
do together in 5 days while C and A together can do in 12 days. In how many days C alone will complete the work?Solution
(A + B)’s 1 day’s work = 1/10 (B + C)’s 1 day’s work = 1/5 (C + A)’s 1 day’s work = 1/12 2 (A +B + C)’s 1 day’s work = 1/10 + 1/5 + 1/12 = (6+12+5)/60 = 23/60 ∴ (A + B + C)’s 1 day’s work = 23/120 Now, C’s 1 day’s work = (A + B + C)’s 1 day’s work – (A + B)’s 1 day’s work, => 23/120 – 1/10 = 11/120 Therefore C will finish the work in = 120/11 = 
days.
23Â Â Â Â 40Â Â Â Â Â Â 67 Â Â Â Â Â Â 104Â Â Â Â Â Â ? Â Â Â Â Â Â 208
...1056Â Â Â Â Â 264Â Â Â Â Â Â 132 Â Â Â Â Â Â 33Â Â Â Â Â Â ? Â Â Â Â Â Â 4.125
...81 72 136 111 ? 278
...48   49    45     54    ?      63      27
...78, 80, 84, ?, 108, 140
What will come in place of the question mark (?) in the following series?
9, 22, 61, ?, 217, 334
562, 628, 698, ?, 850
Find the missing number, in the given number series.
6, 12, 36, ?, 720, 4320
5, 18, 39, 68, 105, ?
What value should come in the place of (?) in the following number series?
14, 18, ?, 43, 68, 104
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