Question
A and B together can do a work in 10 days, B and C can
do together in 5 days while C and A together can do in 12 days. In how many days C alone will complete the work?Solution
(A + B)’s 1 day’s work = 1/10 (B + C)’s 1 day’s work = 1/5 (C + A)’s 1 day’s work = 1/12 2 (A +B + C)’s 1 day’s work = 1/10 + 1/5 + 1/12 = (6+12+5)/60 = 23/60 ∴ (A + B + C)’s 1 day’s work = 23/120 Now, C’s 1 day’s work = (A + B + C)’s 1 day’s work – (A + B)’s 1 day’s work, => 23/120 – 1/10 = 11/120 Therefore C will finish the work in = 120/11 = 
days.
Three series (I, II and III) are given below. Each series contain one odd one out (wrong term) . Wrong term in series I, III and II is denoted by 'P', '...
Two number series are given below, and both follow the same pattern. Series I contains a missing term (m + 18). Find the value of the missing term and ...
28         57           172           689          ?              20677
...112    162    199    ?     242    252
...16 9 ? 13.25 22.625 36.3125
...11, 12, 16, 25, ?, 66
94Â Â Â Â Â Â Â Â Â Â 282Â Â Â Â Â Â Â Â 284Â Â Â Â Â Â Â Â 852Â Â Â Â Â Â Â Â 856Â Â Â Â Â Â Â Â 2562
...Direction: Which of the following will replace ‘?’ in the given question?
5, 18, ‘?’, 126, 296, 586, 1044
520Â Â 79Â Â 440Â Â 151Â Â Â 376Â Â Â ?
9999 6666 ? 2962.66 1975.11 1316. 74
...
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