Get Started with ixamBee
Start learning 50% faster. Sign in now
(A + B)’s 1 day’s work = 1/10 (B + C)’s 1 day’s work = 1/5 (C + A)’s 1 day’s work = 1/12 2 (A +B + C)’s 1 day’s work = 1/10 + 1/5 + 1/12 = (6+12+5)/60 = 23/60 ∴ (A + B + C)’s 1 day’s work = 23/120 Now, C’s 1 day’s work = (A + B + C)’s 1 day’s work – (A + B)’s 1 day’s work, => 23/120 – 1/10 = 11/120 Therefore C will finish the work in = 120/11 = 
days.
If all the number 85243679 are arranged in descending order from left to right, the position of how many numbers will remain unchanged?
How many pairs of letters are there in the word “SAMPLING” which has as many letters between them in the word as in the English alphabetical series?...
How many pairs of letters are there in the word ‘ DETERGENT ’ which has as many letters between them (both forward and backward) in the word as in t...
The position of how many alphabets will remain unchanged if each of the alphabets in the word ‘ PERFORMANCE ’ is arranged in alphabetical order from...
If we increase each even digit by 1 and decrease each odd digit by 1 in the number "8753652846" and then arrange all the digits in ascending order, then...
How many pairs of letters are there in the word “COMPLICATION” which has as many letters between them in the word as in the English alphabetical ser...
