Question
A and B together can do a work in 10 days, B and C can
do together in 5 days while C and A together can do in 12 days. In how many days C alone will complete the work?Solution
(A + B)’s 1 day’s work = 1/10 (B + C)’s 1 day’s work = 1/5 (C + A)’s 1 day’s work = 1/12 2 (A +B + C)’s 1 day’s work = 1/10 + 1/5 + 1/12 = (6+12+5)/60 = 23/60 ∴ (A + B + C)’s 1 day’s work = 23/120 Now, C’s 1 day’s work = (A + B + C)’s 1 day’s work – (A + B)’s 1 day’s work, => 23/120 – 1/10 = 11/120 Therefore C will finish the work in = 120/11 =
days.
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?