Question
A container has a mixture of two liquids, A and B, in
the ratio of 5:3. If 16 liters of the mixture are removed and replaced with 16 liters of liquid B, the ratio of liquids A and B becomes 3:5. Find the initial quantity of liquid A in the container.Solution
ATQ, Let the initial quantity of liquid A be 5x liters and liquid B be 3x liters. After removing 16 liters, 10 liters of A and 6 liters of B are removed. The remaining amounts are: Liquid A: 5x - 10 liters. Liquid B: 3x - 6 liters. After adding 16 liters of liquid B, the new amount of liquid B is 3x + 10 liters. Given the new ratio of A to B is 3:5: (5x - 10) / (3x + 10) = 3 / 5. Cross-multiplying and solving: 25x - 50 = 9x + 30, 16x = 80, so x = 5. Thus, the initial quantity of liquid A is 5 × 5 = 25 liters.
(10.98% of 499.99) - 4.998 = √?
[(5/6 of 720.21) + 39.79% of 550.14] × (√120.91 + 29.99% of 200.09) = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
The number of men, women and children in a village are in the ratio of 3:2:5 respectively. If total population of men is 2700, then find the average pop...
(24.78 × 11.67) + (7199.67 ÷ 14.99) = ? × 12.65Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
25, 28, 26, 29, 27, ?
(1488.06 × 4.99) - 5677.95 + 1038.06 - 658.97 + (272.95 × 3.05) = ? × (36.95 × 4.02)
