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ATQ,
Sum of height of the players = 185 × 18 = 3330 cm Sum of height of the players and coaches = 186.5 × 20 = 3730 cm So, the sum of height of the coaches = 3730 - 3330 = 400 cm So, the required average = (400/2) = 200 cm Alternate Solution: Change in the average = 186.5 - 185 = 1.5 cm Because of the addition of 2 coaches, the height of 20 members (18 players + 2 coaches) is considered. So, the additional height added to the players' total height = 1.5 × 20 = 30 cm So, the sum of the heights of the two coaches = 2 × 185 + 30 = 370 + 30 = 400 cm So, the required average = (400/2) = 200 cm
(53 + 480 ÷ 4)% of 20 = ?% of 70
(47.5 ÷ 9.5) × (78.5 ÷ 15.7) + 475 = ? + 15% of 150
If 840 ÷ 12 + 1025 ÷ 25 - n + 45 × 4 = 960 ÷ 16 × 132 ÷ 44, then the value of n is:
What will come in the place of question mark (?) in the given expression?
133 ÷ 19 X √576 + ? ÷ 2 = 32 X 7.5
Find the value of 'p' in the given expression: 15 of 6 ÷ p x 4 = 30.
(630 ÷ 35) × 2 + 144 = ? × 2
(62 - 52 ) % of 800 = 22 X √?