Question
A car moving at 15 m/s noticed another car ahead moving
at 9 m/s and accelerated to catch it. If the distance between them was 180 metres, find the time required to catch the slower car.Solution
Relative speed of faster car w.r.t slower car = 15 − 9 = 6 m/s
So, required time = 180 ÷ 6 = 30 seconds
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