Question
The distance between two points 'E' and 'F' is 2,100 km.
Vikram and Sameer can cover the distance between 'E' and 'F' in 42 hours and 35 hours, respectively. If Vikram and Sameer start from point 'E' at 11:00 AM and 1:00 PM, respectively, then at what time and distance from point 'E' will they meet each other?Solution
ATQ, Speed of Vikram = (2,100/42) = 50 km/h Speed of Sameer = (2,100/35) = 60 km/h Distance covered by Vikram in 2 hours (from 11:00 AM to 1:00 PM) = 50 X 2 = 100 km Relative speed of Sameer w.r.t. that of Vikram = 60 - 50 = 10 km/h Time taken by them to meet each other = (100/10) = 10 hours So, required time = 1:00 PM + 10 hours = 11:00 PM Required distance = 60 X 10 = 600 km
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
25.04 × 22.03 + 383.92 ÷ ? + 23.78% of 1499.98 = 926.08Â
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
256.12 ÷ 7.92 + 26.11 × 7.82 – 44.09 = ?2Â
657.94 + 335.21 - 211.09 - 82.30 = ?
27.27% of 5501.22 + 12.53% of 158.99 – √ 1599 = ?
(3.21) ? + 37.92 ÷ 1.98 = (5.99 + 3.99) 2
- 27.99² - 40.02% of 419.99 + √3135.99 = ? X 5.99
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