Question
A cyclist moving at (6/7) of his regular speed reaches
his school 20 minutes late. Find the usual time he takes to reach school.Solution
ATQ, When distance is constant, Time ā (1 / Speed) Ratio of usual time to new time = 6 : 7 Let usual time = 6t and new time = 7t. 7t ā 6t = 20 ā t = 20 Usual time = 6t = 6 Ć 20 = 120 minutes
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