Question
A girl walks to her college at (5/6) of her normal speed and reaches 25 minutes late. Find how long she normally takes to reach college.
Solution
ATQ, When distance is constant, Time ∝ (1 / Speed) Ratio of usual time to new time = 5 : 6 Let usual time = 5t and new time = 6t. 6t – 5t = 25 ⇒ t = 25 Usual time = 5t = 5 × 25 = 125 minutes
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