Akshat and Saksham were allotted two locations for their kiosks. The distances from their home are 24 km and 36 km respectively. They left together and reached their respective locations exactly at 9:00
A.M. One day, their locations were swapped. To reach on time, Akshat started 20 minutes earlier than Saksham. Find the speed of Akshat.

ATQ, ATQ, Distance covered by Akshat and Saksham = 24 km and 36 km, respectively Since, both of them reached their respective places at same time Therefore, ratio of speeds of Akshat and Saksham = 24:36 = 2:3 Let the speeds of Akshat and Saksham be 2x km/hr and 3x km/hr, respectively Time taken by Akshat on the day of interchange = 36/(2x) hours Time taken by Saksham on the day of interchange = 24/(3x) hours According to the question, (36/(2x)) – (24/(3x)) = 20/60 Or, (18/x) − (8/x) = 1/3 Or, 10/x = 1/3 Or, x = 30 Therefore, speed of Akshat = 2x = 60 km/hr