Question
An individual "P" needs to cover
a total distance of 516 km. They travel 6 km less than half of the total distance at a speed of 48 km/h, followed by (7/12)th of the remaining distance at a speed of 44 km/h. If the total time taken for the journey is 11.5 hours, determine the speed at which "P" traveled the final segment of the journey.Solution
ATQ, Distance travelled at speed of 48 km/h = 516 × 0.5 - 6 = 252 km So, time taken to travel 252 km = 252 ÷ 48 = 5.25 hours Remaining distance = 516 - 252 = 264 km (7/12)th of the remaining distance = 264 × (7/12) = 154 km Time taken to travel 154 km = 154 ÷ 44 = 3.5 hours Remaining distance to be travelled = 516 - (252 + 154) = 110 km Remaining time = 11.5 - (5.25 + 3.5) = 2.75 hours So, speed at which remaining distance to be travelled = 110 ÷ 2.75 = 40 km/h So, 'P' travelled the last part of the journey at the speed of 40 km/h
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