Sheetal’s speed= 40 km/hr. Time taken by Sheetal = 5 hrs. Distance = Speed × Time = 40 × 5 = 200 km. ∴ Distance covered by Hemlata = 200 km. Time taken by Hemalata = 4 hrs. ∴ Hemlata’s Speed = (Distance )/Time = (200 )/4 = 50 km/hr. Sheetal’s increased speed= 40 + 10 = 50 km/hr. ∴ Time taken by Sheetal = (200 )/50 = 4 hrs. Hemlata’s increased speed = 60 km/hr. ∴ Time taken by Hemlata = (200 )/60 = 31/3 hrs. = 3hrs 20 minutes. ∴ Required difference = 4 hrs – 3hrs 20 minutes = 40 minutes.
Central Potato Research Institute is situated in_____
Which is used in the control of water hyancinth
Trashing, Arrowing and Ratooning are common practices in
Soil water is lost from the soil surface and from the rooting zone of the plant by the following respectively
Lalit and Shweta are the varieties of:
Which of the following is a major greenhouse gas released by agricultural activities?
What management practice is recommended for controlling Papaya Ringspot Virus?
The instrument used for measuring depth of water table is known as:
Which of these statements is incorrect?
A. Glycolysis occurs in cytosol
B. Oxidative phosphorylation takes place in outer mitochondrial ...
Heavy shedding of buds and bolls occurs in cotton due to:
