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    Question

    Sheetal rides a bike at an average speed of 40 kmph and

    reaches her destination in 5 hours. Hemlata covers the same distance in 4 hrs. If Sheetal increases her average speed by 10 kmph and Hemlata increases her average speed by 10 kmph, what would be the difference in their time taken to reach destination?
    A 55 min Correct Answer Incorrect Answer
    B 48 min Correct Answer Incorrect Answer
    C 50 min Correct Answer Incorrect Answer
    D 40 min Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Sheetal’s speed= 40 km/hr. Time taken by Sheetal = 5 hrs. Distance = Speed × Time = 40 × 5 = 200 km. ∴ Distance covered by Hemlata = 200 km. Time taken by Hemalata = 4 hrs. ∴ Hemlata’s Speed = (Distance )/Time = (200 )/4 = 50 km/hr. Sheetal’s increased speed= 40 + 10 = 50 km/hr. ∴ Time taken by Sheetal = (200 )/50 = 4 hrs. Hemlata’s increased speed = 60 km/hr. ∴ Time taken by Hemlata = (200 )/60 = 31/3 hrs. = 3hrs 20 minutes. ∴ Required difference = 4 hrs – 3hrs 20 minutes = 40 minutes.

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