Question
Bike 'P' runs at (6/5) the speed of Bike 'Q'. Both bikes
started from the same location and reached the same place at the same time. If Bike 'P' paused for 75 minutes on the way, and each bike travelled 300 km, what is the speed difference between Bike 'P' and Bike 'Q'?Solution
ATQ,
vP = (6/5) vQ Distance = 300 km each Pause by P = 1.25 h t = time for Q → vQ = 300 / t Time for P = t - 1.25 → 300 = (6/5) * vQ * (t - 1.25) Sub vQ: 300 = (6/5) * (300/t) * (t - 1.25) 1 = (6/5) * (1 - 1.25/t) 0.2 = 1.5 / t → t = 7.5 vQ = 300 / 7.5 = 40 km/h vP = 48 km/h Speed difference = 8 km/h
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