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      Question

      Bike 'P' runs at (6/5) the speed of Bike 'Q'. Both bikes

      started from the same location and reached the same place at the same time. If Bike 'P' paused for 75 minutes on the way, and each bike travelled 300 km, what is the speed difference between Bike 'P' and Bike 'Q'?
      A 12 km/h Correct Answer Incorrect Answer
      B 18 km/h Correct Answer Incorrect Answer
      C 8 km/h Correct Answer Incorrect Answer
      D 24 km/h Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      ATQ,

      vP = (6/5) vQ Distance = 300 km each Pause by P = 1.25 h t = time for Q → vQ = 300 / t Time for P = t - 1.25 → 300 = (6/5) * vQ * (t - 1.25) Sub vQ: 300 = (6/5) * (300/t) * (t - 1.25) 1 = (6/5) * (1 - 1.25/t) 0.2 = 1.5 / t → t = 7.5 vQ = 300 / 7.5 = 40 km/h vP = 48 km/h Speed difference = 8 km/h

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