Question
If Sneha cycles a certain distance at 9 km/h, she
arrives 7 hours late. If she cycles at 15 km/h, she reaches 2 hours early. What is 80% of the distance Sneha covered?Solution
ATQ:
Let the distance travelled by Sneha = ‘d’ km
Let the usual time taken by Sneha to travel this distance = ‘t’ hours We have,
d ÷ 9 = t + 7…………………..(i)
Also, d ÷ 15 = t – 2…………………(ii) Equation (i) – Equation (ii), we get
(d/9) – (d/15) = t + 7 – (t – 2) = 9
Or, (5d – 3d) ÷ 45 = 9
So, d = (45 × 9) ÷ 2 = 202.5 So, 80% of the distance travelled by Sneha = 202.5 × 0.8 = 162 km
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