A man travels some distance at a speed of 20 km/hr and returns at a speed of 15 km/hr. If the total time taken by him is 2 hrs 20 min, the distance is
Let the distance travelled by a man be D km According to the question, Total time taken = 2 hrs 20 min = 2(20/60) = 7/3 hours Total time = T1 + T2 D/20 + D/15 = 7/3 (3D + 4D)/60 = 7/3 7D/60 = 7/3 D = 20 km
IPv6 addresses have a size of:
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