Question
βIβ and βJβ are going from place βVβ to
place βWβ, which is 1350 km apart. If βIβ started 3 hours after βJβ but both of them reached βWβ at the same time, then find the speed of βJβ. The difference between their speeds is 30 km/hr.Solution
ATQ, Let the speed of βIβ be βaβ km/hr Therefore, speed of βJβ = (a β 30) km/hr According to the question, 
Since speed cannot be negative therefore, a = 150 Therefore, speed of βJβ = a - 30 = 120 km/hr
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