Question
βKβ and βLβ are going from place βXβ to
place βYβ, which is 1100 km apart. If βKβ started 3 hours after βLβ but both of them reached βYβ at the same time, then find the speed of βLβ. The difference between their speeds is 20 km/hr.Solution
ATQ, Let the speed of βKβ be βbβ km/hr Therefore, speed of βLβ = (b β 20) km/hr According to the question, 
Since speed cannot be negative therefore, b = 100 Therefore, speed of βLβ = b - 20 = 80 km/hr
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