Question
'A' and 'B' are running on a circular track of length
4000 metres. 'A' is running clockwise at 8 m/s while 'B' is running anti-clockwise at 10 m/s. Find the difference between the distance covered by 'A' and 'B' by the time they meet for the tenth time.Solution
ATQ, Time taken to meet for the first time = 4000 ÷ (8 + 10) = 250 seconds So, time taken to meet for 10th time = 250 × 10 = 2500 seconds So, distance covered by 'A' in 2500 seconds = 2500 × 8 = 20000 metres And distance covered by 'B' in 2500 seconds = 2500 × 10 = 25000 metres So, required difference = 25000 - 20000 = 5000 metres
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