Question
'A' and 'B' are running on a circular track of length
5000 metres. 'A' is running clockwise at 6 m/s while 'B' is running anti-clockwise at 8 m/s. Find the difference between the distance covered by 'A' and 'B' by the time they meet for the tenth time.Solution
ATQ, Time taken to meet for the first time = 5000 ÷ (6 + 8) = 312.5 seconds So, time taken to meet for 10th time = 312.5 × 10 = 3125 seconds So, distance covered by 'A' in 3125 seconds = 3125 × 6 = 18750 metres And distance covered by 'B' in 3125 seconds = 3125 × 8 = 25000 metres So, required difference = 25000 - 18750 = 6250 metres
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