Question
'A' and 'B' are running on a circular track of length
4500 metres. 'A' is running clockwise at 5 m/s while 'B' is running anti-clockwise at 7 m/s. Find the difference between the distance covered by 'A' and 'B' by the time they meet for the tenth time.Solution
ATQ, Time taken to meet for the first time = 4500 ÷ (5 + 7) = 375 seconds So, time taken to meet for 10th time = 375 × 10 = 3750 seconds So, distance covered by 'A' in 3750 seconds = 3750 × 5 = 18750 metres And distance covered by 'B' in 3750 seconds = 3750 × 7 = 26250 metres So, required difference = 26250 - 18750 = 7500 metres
What is the name of the device that is used to send and receive data over a computer network?
With regard to a word processing software, the process of combining static information in a publication together with variable information in a data sou...
Which memory type retains its data even when the power is turned off?
What is the purpose of the OSI (Open Systems Interconnection) model in computer networks?
Which of the following browser was recommend by Microsoft?
Examples of fax machines and imaging systems fall under the category of:
Which protocol is responsible for converting the logical address to a physical address?
A digital signal is a series of discrete values. These values are represented in binary as 1's and 0's. This is a characteristic of which type of comput...
Where is the basic input/output system (BIOS) stored?
Which type of socket is commonly used for connecting a graphics card to a motherboard?
