Question
Amit walks for 2 hours at a speed of 's' km/hr, and then
his speed increases by 25 km/hr, covering the remaining distance in 3 hours. If Amit's speed had increased by 20% after 2 hours, and he walked for 5 hours, the total distance covered would have been 30 km more than the initial distance. Determine the initially covered total distance.Solution
ATQ, 1.2s × 5 – (s + 25) × 3 = 30 Or, 6s – 3s = 105 Or, s = 105/3 = 35 Therefore, total distance travelled initially = 2s + 3(s + 25) = 250 km
1885 ÷ 64.98 + 7.29 + ? = 69.09
212 + 14 × 23 – 28 × 15 = ? Â
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
567-4824 ÷ 134 =? × 9
Determine the value of 'p' in the expression.
28 ÷ 22p + 1 = 43Â
What will come in place of (?) in the given expression.
(15) ² - (13) ² = ?? = 6.25% of 240 + 25 2 + 17 2 – 16 × 17
35% of 840 + 162 = ? – 25% × 300
(7/5) × (3/4) × (5/9) × (6/7) × 3112 = ?
1024 ÷ 16 + 800 ÷ √64 + ? = 200 * 2