Amit walks for 2 hours at a speed of 's' km/hr, and then his speed increases by 25 km/hr, covering the remaining distance in 3 hours. If Amit's speed had increased by 20% after 2 hours, and he walked for 5 hours, the total distance covered would have been 30 km more than the initial distance. Determine the initially covered total distance.
ATQ, 1.2s × 5 – (s + 25) × 3 = 30 Or, 6s – 3s = 105 Or, s = 105/3 = 35 Therefore, total distance travelled initially = 2s + 3(s + 25) = 250 km
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