Question
Due to walking at (3/4) of his normal speed, a boy reaches
school 18 minutes late. What is the time he normally takes to go to school?Solution
ATQ,
When distance is constant,
Time ∝ (1/Speed)
So, time ratio = 3:4
Let usual time = 3t and new time = 4t
4t – 3t = 18
t = 18
Usual time = 3t = 3 × 18 = 54 minutes
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