Question
The bike reduces its speed by 20 km/h and, because of
this reduction, it takes 50% more time to cover the same distance as before. Find, the original speed of the bikeSolution
ATQ, Let the bike’s original speed = v km/h Reduced speed = (v − 20) km/h Given: New time is 50% more than original time So, for the same distance D: D/(v − 20) = 1.5 × D/v Cancel D: 1/(v − 20) = 1.5/v Cross-multiply: v = 1.5(v − 20) v = 1.5v − 30 0.5v = 30 v = 60 km/h So, bike’s original speed = 60 km/h
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