Question
In a 50 km race, R, S, and T are running at uniform speed.
If ‘R’ beats ‘S’ by 10 km, and ‘S’ beats ‘T’ by 6 km, then by how many metres does ‘R’ beat ‘T’?Solution
ATQ,
When ‘R’ covers 50 km, ‘S’ will cover 40 km
Similarly, when ‘S’ covers 50 km, ‘T’ covers 44 km
Therefore, when ‘S’ covers 40 km, then ‘T’ will cover = (40 × 44) / 50 = 35.2 km
Therefore, ‘R’ will beat ‘T’ by = 50 – 35.2 = 14.8 km = 14800 metres
1219.98 ÷ 30.48 × 15.12 = ? × 2.16
(1177.99 + 226.99 + 94.923) ÷ 24.97% of 59.989 = ?
447.79 ÷ √(√2400) + 30.94 × 6.07 – 5.08 × 21.96 = ?
7/12 of 539.98 – 23.98 × 9.03 + 77.89 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
[(2/3 of 599.77) + (39.69% of 450.14)] ÷ [(5/8 of 399.79) - √120.91] = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
Find the approximate value of Question mark(?). No need to find the exact value.
(639.78 ÷ 15.96) × 5 + 30.14% of 349.88 – √(224.95) ÷ 5...
(5/9 of 2699.81) + (49.88% of 144.18) - (2/7 of 489.77) = ?
(39.933% of 30.03) - (27.78 `xx` 15.30) = ? - (40 `xx` 38.87)
