Question
If a car runs at 45 km/hr, it reaches its destination
late by 13 minutes but if runs at 60 km/hr it is late by 7 minutes. What is the correct time for the journey?Solution
Distance = Difference in time x (S1 x S2)/(S1 β S2) D = [13 β 7]/60 x {(45 x 60)/[60 β 45]} => (6/60) x (60 x 50)/15 => 18 km Time, T = D/S (take any one of the speed) => 18/45 = 18/45 x 60 = 24 minutes Then, correct time is 24 β 13 = 11 minutes
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