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Suppose the speeds of the two trains x m/sec and 3x m/sec respectively. Also, suppose that the lengths of the two trains are A m and B m respectively. Then, ((A+B)/(3x - x)) = 50 ……………….. (i) and (A/(3x - x)) = 20 ……………… (ii) Dividing (i) by (ii), we get ((A+B)/A) = 50/20 B/A + 1 = 5/2 B/A = 3/2 or A:B = 2:3
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