Question
A driver of an army truck sees an ambulance 80 meters
ahead of him. After 10 seconds the ambulance is 70m behind. If the speed of the truck is 104kmph, then what is the speed of the ambulance?Solution
Relative speed = totaldistance/totaltime = (70+80)/10 = 15 m/sec Speed in km/hr = 15 ×18/5 = 54 km/hr Relative speed = speed of truck – speed of ambulance 54 = 104 – speed of ambulance Speed of ambulance = 104 – 54 = 50km/hr
{5% of (20 × 25) + 6% of (30 ×35)} ÷ 11 = ?Â
? = 120% of (652 ÷ 132 ) + 33 × 8
[{70 + (40 - 22) ÷ 3} ÷ 4] = ?
Find the simplified value of the given expression.
(1/4) of {64Â - 28 x 15 + 13 x 16 - 12.5 of 122}
What will come in the place of question mark (?) in the given expression?
642 - 362 = ? X √1225
? = 6.25% of 240 + 252 + 172 – 16 × 17

- What will come in place of (?), in the given expression.
144 ÷ 12 + 18 × 2 = ? What will come in the place of question mark (?) in the given expression?
(50 × 6 ÷ 12) × 9 = ?
25639 – 5252 – 3232 = ?