Question
One day, 'A' arrived at the bus stop 10 minutes late.
The next day, he increased the speed of his bicycle by 5 km/h, which helped him reach the bus stop on time. If the distance from his home to the bus stop is 130 km, what was the speed of 'A's cycle on the day he increased his speed?Solution
ATQ, Let 'A's normal speed be ‘s’ km/h. Time taken to reach the Bus stop at normal speed = (130/s) hour Now, after increasing the normal speed by 5 km/h. New speed will be = (s + 5) km/h Time taken to reach the Bus stop at new speed = 130/(s + 5) hour According to the given information, 130/s – 130/(s + 5) = 1/6 s2 + 5s – 3900 = 0 s2– 60s + 65s – 3900 = 0 s(s – 60) + 65(s – 60) = 0 (s –60)(s + 65) = 0 Therefore, s = 60 km/h Therefore, his increased speed on that day = 60 + 5 = 65 km/h
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