Question
Walking at (5/6) of his usual speed, a man reaches the bus
stop 20 minutes late. Find the time he usually takes to reach the bus stop.Solution
ATQ,
When distance is constant,
Time ∝ (1/Speed)
So, the ratio of time taken at usual speed to the time taken at new speed = 5:6
Let the usual time be ‘5t’ minutes and new time be ‘6t’ minutes.
6t – 5t = 20
t = 20
So, usual time = 5t = 5 × 20 = 100 minutes
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