Question
Ravi travels from town X to town Y. At 20 km/h he reaches 4
hours late, but at 50 km/h, he reaches 2 hours early. Find the distance between town X and town Y.Solution
ATQ,
Let the distance = 'd' km
Let the usual time = 't' hours
Then, (d/20) = t + 4
Or, t = (d/20) - 4
And, (d/50) = t - 2
Or, t = (d/50) + 2
So, (d/20) - 4 = (d/50) + 2
Or, (d/20) - (d/50) = 6
LCM of 20 and 50 = 100
Or, (5d - 2d)/100 = 6
Or, 3d = 600
So, d = 200
Therefore, the distance = 200 km
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