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D1= 200 Km, S1= 50 Km/hr, D2= 160 Km, S2 = 80 Km/hr, D3= 80 Km, S3= 40 km/hr. T1= (Distance )/Speed = (200 )/50 = 4 hr. T2 = (Distance )/Speed = (160 )/80 = 2 hr. T3= (Distance )/Speed = (80 )/40 = 2 hr. Average Speed= (Total Distance )/(Total Time) = (440 )/8 = 55 km/hr.
(18 2 – 17 2) x (1/5) + ? = 148
18 × 15 + 86 – 58 =? + 38
8(3/4) + 5(1/6) – 4(3/4) = ?
∛857375 + ∛91125 = ? + √6889
The value of 97 × 103 is _________.
125% 0f 74÷37×48×? =192 ×√225
(25.111 % of 200) × 26 ÷ 12.99 – 18.88 × 15.82 + 150.33% of 3√ 4917 = ? – 200
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