Question
Average speed of βAβ during a 20-hour journey is 20
km/h. If he covered the first 200 km of his journey at a speed of 20 km/h, then find the speed at which βAβ travelled during the remaining journey.Solution
Total distance covered by βAβ = 20 Γ 20 = 400 km Time taken to cover 200 km = 200/20 = 10 hours Time taken to cover remaining distance = 20 β 10 = 10 hours So, required speed = {(400 β 200)/10} = 20 km/h
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