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ATQ, Let total work = 420 days (LCM of 84, 105 and 60) Amount of work completed by Anuj in one day = 420/84 = 5 units Amount of work completed by Bittu in one day = 420/105 = 4 units Amount of work completed by Chintu in one day = 420/60 = 7 units Amount of work completed by Anuj, Bittu and Chintu together in 12 days = 12 × (5 + 4 + 7) = 192 units Amount of time taken by Anuj and Chintu together to complete the remaining work = (420 – 192)/12 = 19 days Desired time = 12 + 19 = 31 days
(√4623.9 + √484.2) – √2303.97 ÷ √1296.4 × √35.98 ÷ √15.99 = ?
√2025.12 × √256.03 + √399.89 ×√(?) = 33.99 × 40.12
9214.39 - 6843.57 + 8435.22 + ? = 17620.47
44.78% of 715.62 + 1785% of 42.98 = ?
(16.16 × 31.98) + 24.15% of 649.99 = ? + 124.34
1279.908 + 1499.897 ÷ 29.912 × 22.22 = ? + 82.210 × 4.908
? 2 – 17.89 2 + 15.33% of 1199.76 = 49.54% of 49.68
31.98% of 224.99 = 24.98% of ? + 9.91% of 499.99
4.93% of 539.92-48% of 4700=?-8330.33
Find the approximate value of Question mark(?). No need to find the exact value.