Question
The speed ratio of A to B is 4:3. C covers 840 km in 14
hours. If B's speed is 20% lower than C's speed, how much time will A need to cover 512 km?Solution
ATQ,
Speed of C = 840/14 = 60 km/hr So, speed of B = 0.8 × 60 = 48 km/hr Therefore, speed of A = (4/3) × 48 = 64 km/hr Therefore, required time = 512/64 = 8 hours
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