Question
 If a car runs at 30 km/hr, it reaches its destination
late by 12 minutes but if runs at 44 km/hr it is late by 5 minutes. What is the correct time for the journey?Solution
Distance = Difference in time x (S1 x S2)/(S1 – S2) D = [12 – 5]/60 x {(44 x 30)/[44 – 30]} => (7/60) x (44 x 30)/14 => 11 km Time, T = D/S (take any one of the speed) => 11/30 = 11/30 x 60 = 22 minutes Then, correct time is 22 – 12 = 10 minutes
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