Question
If a car runs at 40 km/hr, it reaches its destination
late by 14 minutes but if runs at 50 km/hr it is late by 8 minutes. What is the correct time for the journey?Solution
Distance = Difference in time x (S1 x S2)/(S1 β S2) D = [14 β 8]/60 x {(50 x 40)/[50 β 40]} => (6/60) x (50 x 40)/10 => 20 km Time, T = D/S (take any one of the speed) => 20/40 = 20/40 x 60 = 30 minutes Then, correct time is 30 β 14 = 16 minutes
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