Question
If a car runs at 36 km/hr, it reaches its destination
late by 15 minutes but if runs at 45 km/hr it is late by 9 minutes. What is the correct time for the journey?Solution
Distance = Difference in time x (S1 x S2)/(S1 – S2) D = [15 – 9]/60 x {(45 x 36)/[45 – 36]} => (6/60) x (45 x 36)/9 => 18 km Time, T = D/S (take any one of the speed) => 18/36 = 18/36 x 60 = 30 minutes Then, correct time is 30 – 15 = 15 minutes
12Â Â Â Â Â Â Â Â Â Â Â Â Â 10Â Â Â Â Â Â Â Â Â Â Â Â 13Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 18.5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 25.50Â Â Â Â Â Â Â ...
7, 14, 42, 210, 1470, ?
6, 17, 21, 47, ?, 107
21     84      168      172     ?     348
...315 146 267 ? 235 210
14 20 35 ? 433 2167
...18, 32, 50, 82, 132, ?
840 400 180 ? 15 -12.5
...22Â Â Â 23Â Â Â Â 32Â Â Â Â 57Â Â Â 106Â Â Â ?
Three series are given below. You have to find the values of P, Q and R, then establish a relationship among them.
I:Â Â Â 210, P , 233, 64,...
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