Question
If a car runs at 40 km/hr, it reaches its destination
late by 12 minutes but if runs at 48 km/hr it is late by 8 minutes. What is the correct time for the journey?Solution
Distance = Difference in time x (S1 x S2)/(S1 – S2) D = [12 – 8]/60 x {(40 x 48)/[48 – 40]} => (4/60) x (48 x 40)/8 => 16 km Time, T = D/S (take any one of the speed) => 16/40 = 16/40 x 60 = 24 minutes Then, correct time is 24 – 12 = 12 minutes
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 20x + 96 = 0
Equation 2: y² - 18y + 72 = 0
I. 56x² - 99x + 40 = 0
II. 8y² - 30y + 25 = 0
I. 7x² + 52x + 21 = 0
II. 6y² + 7y - 24 = 0
I. 96x² + 52x - 63 = 0
II. 77y² + 155y + 72 = 0
I. x2 + 16x + 63 = 0
II. y2 + 2y - 15 = 0
I. 104x² + 9x - 35 = 0
II. 72y² - 85y + 25 = 0
I. 9x2 + 45x + 26 = 0
II. 7y2 – 59y − 36 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 40x + 300 = 0
Equation 2: y² - 30y + 216 = 0
I.√(3x-17)+ x=15
II. y + 135/y=24
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 21x² - 82x + 80 = 0
Equation 2: 23y² - 132y + 85 = 0
