Question
If a car runs at 40 km/hr, it reaches its destination
late by 12 minutes but if runs at 48 km/hr it is late by 8 minutes. What is the correct time for the journey?Solution
Distance = Difference in time x (S1 x S2)/(S1 – S2) D = [12 – 8]/60 x {(40 x 48)/[48 – 40]} => (4/60) x (48 x 40)/8 => 16 km Time, T = D/S (take any one of the speed) => 16/40 = 16/40 x 60 = 24 minutes Then, correct time is 24 – 12 = 12 minutes
More Time and distance Questions
30, 39, 66, ? , 174, 255
What will come in the place of question mark (?) in the given expression?
(555 + 385 - 535) ÷ 15 X ? = 36 X 30
30% of 40% of 120% of 3500 = ? × 63
Find the simplified value of the given expression:
8 of 7 ÷ 2 × 5² + √36 – 10√ 729 × 5 – 220 % of 15 + ? = 120% of 160
35% of 500 × 22% of ? = 847
(200 + 50% of 120) ÷ (9 × 2) = ?
779 + 136 – 334 = 270 + 121 + ?
525 ÷ 21 x 28 – 853 + 264 = ?
1885 ÷ 64.98 + 7.29 + ? = 69.09
