Question
In a 2 km race, 'X' allows 'Y' a lead of 400 metres, but
still beats him by 200 metres. If 'Y' finishes the race in 20 minutes, how much time does 'X' take to finish?Solution
ATQ,
Distance covered by 'Y' when 'X' covers 2000 m = 2000 - 400 - 200 = 1400 m
Ratio of speeds (X : Y) = 2000 : 1400 = 10 : 7
Time ratio = 7 : 10
Time taken by X = (20/10) × 7 = 14 minutes
12 11 18 34 89.5 259.5
...Three series are provided below. You need to determine the values of A, B, and C and subsequently establish a relationship among them.
I: 4, 10...
60000 2400 120 8 0.8 ?
...32, ?, 41, 68, 132, 257
...11Â Â 34Â Â 135Â Â 676Â Â 4055Â Â Â ?
261Â Â Â Â Â 256Â Â Â Â Â Â 246Â Â Â Â Â Â 231Â Â Â Â Â 211Â Â Â Â Â ?
...Choose the number which is different from others in the group.
20Â Â Â 60Â Â Â Â 150Â Â Â Â 300Â Â Â 450Â Â Â ?
17Â Â Â Â Â ? Â Â Â Â Â 2142 Â Â Â Â Â Â 12852 Â Â Â Â Â Â 64260Â Â Â Â Â Â 257040
...6   55   91   116   132    ?  . Â
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