Question
The speed of two cars A and B are in the ratio of 14:19
respectively. Car A travels 15 km less than the car B in the same time duration. What was the distance (in km) travelled by the car B during that time?Solution
Let the speed of car A = 14x km/h and the speed of car B = 19x km/h. Here the time is constant. According to question, => 19x – 14x = 15 => 5x = 15 => x = 3 Distance travelled by car B = 19 × 3 = 57 km
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Statements:
O ≤ W ≥ B > A ≤ U; X< U ≤ L
Conclusions:
I) B > X
II) W ≤ L
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