Question
Ajay and Vishal left the place ‘X’ with different
speeds which are in the ratio 3:2 respectively. Ajay left the place 42 seconds after Vishal. If after 72 seconds of the departure of Vishal, Ajay is 40 meters apart from Vishal, then find the speed of Vishal.Solution
Let the speeds of Ajay and Vishal be 3x and 2x km/hr respectively. Distance covered by Vishal in 72 seconds = 2x x (5/18) x 72 = 40x m Distance covered by Ajay in 42 seconds = 3x x (5/18) x 42 = 35x m According to the question, => 40x – 35x = 40 => x = 8 Therefore the speed of Vishal = 2x = 16 km/hr
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