Question

    Ajay and Vishal left the place ‘X’ with different

    speeds which are in the ratio 3:2 respectively. Ajay left the place 42 seconds after Vishal. If after 72 seconds of the departure of Vishal, Ajay is 40 meters apart from Vishal, then find the speed of Vishal.
    A 16 km/hr Correct Answer Incorrect Answer
    B 32 km/hr Correct Answer Incorrect Answer
    C 25 km/hr Correct Answer Incorrect Answer
    D 20 km/hr Correct Answer Incorrect Answer
    E 18 km/hr Correct Answer Incorrect Answer

    Solution

    Let the speeds of Ajay and Vishal be 3x and 2x km/hr respectively. Distance covered by Vishal in 72 seconds = 2x x (5/18) x 72 = 40x m Distance covered by Ajay in 42 seconds = 3x x (5/18) x 42 = 35x m According to the question, => 40x – 35x = 40 => x = 8 Therefore the speed of Vishal = 2x = 16 km/hr

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