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    Question

    TYPE 16

    Ajay and Vishal left the place ‘X’ with different

    speeds which are in the ratio 9:5 respectively. Ajay left the place 36 seconds after Vishal. If after 72 seconds of the departure of Vishal, Ajay is 40 meters apart from Vishal, then find the speed of Vishal.
    A 16 km/hr Correct Answer Incorrect Answer
    B 12 km/hr Correct Answer Incorrect Answer
    C 15 km/hr Correct Answer Incorrect Answer
    D 20 km/hr Correct Answer Incorrect Answer
    E 18 km/hr Correct Answer Incorrect Answer

    Solution

    Let the speeds of Ajay and Vishal be 9x and 5x km/hr respectively. Distance covered by Vishal in 72 seconds = 5x x (5/18) x 72 = 100x m Distance covered by Ajay in 36 seconds = 9x x (5/18) x 36 = 90x m According to the question, => 100x – 90x = 40 => x = 4 Therefore the speed of Vishal = 5x = 20 km/hr

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