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    Question

    Ajay and Vishal left the place ‘X’ with different

    speeds which are in the ratio 9:5 respectively. Ajay left the place 36 seconds after Vishal. If after 72 seconds of the departure of Vishal, Ajay is 40 meters apart from Vishal, then find the speed of Vishal. TYPE 16
    A 16 km/hr Correct Answer Incorrect Answer
    B 12 km/hr Correct Answer Incorrect Answer
    C 15 km/hr Correct Answer Incorrect Answer
    D 20 km/hr Correct Answer Incorrect Answer
    E 18 km/hr Correct Answer Incorrect Answer

    Solution

    Let the speeds of Ajay and Vishal be 9x and 5x km/hr respectively. Distance covered by Vishal in 72 seconds = 5x x (5/18) x 72 = 100x m Distance covered by Ajay in 36 seconds = 9x x (5/18) x 36 = 90x m According to the question, => 100x – 90x = 40 => x = 4 Therefore the speed of Vishal = 5x = 20 km/hr

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