Question
Ajay and Vishal left the place ‘X’ with different
speeds which are in the ratio 9:5 respectively. Ajay left the place 36 seconds after Vishal. If after 72 seconds of the departure of Vishal, Ajay is 40 meters apart from Vishal, then find the speed of Vishal. TYPE 16Solution
Let the speeds of Ajay and Vishal be 9x and 5x km/hr respectively. Distance covered by Vishal in 72 seconds = 5x x (5/18) x 72 = 100x m Distance covered by Ajay in 36 seconds = 9x x (5/18) x 36 = 90x m According to the question, => 100x – 90x = 40 => x = 4 Therefore the speed of Vishal = 5x = 20 km/hr
105Â Â Â Â Â Â 112Â Â Â Â Â Â 133Â Â Â Â Â Â Â 168Â Â Â Â Â Â 216Â Â Â Â Â Â 280Â Â Â Â Â Â 357
...In each of the following number series, one term is wrong. Find the wrong term.
3, 7, 13, 21, 31, 42, 57
Find the wrong number in the given number series.
76, 81, 96, 123, 156, 20132, 16, 24, 60, 207, 945
Find the wrong number in the given number series,
121, 130, 116, 139, 103, 148
- Find the wrong number in the given number series.
10, 18, 32, 52, 78, 110 Find the wrong number in the given number series.
8.6, 11.3, 16.7, 24.2, 35.6, 49.1
1600, 1604, 1544, 1760, 1248, 2248, 520
- Find the wrong number in the given number series.
5, 10, 30, 120, 480, 3600 Direction: Find the wrong number in given number series.
640, 663, 713, 794, 920, 1065
