Question
If a person walks 20% more than of his usual speed,
reaches his distance 90 minutes before. If the destination is 459 km away, then the usual speed of a person is (in km/hr)?Solution
Let the usual speed be x km/hr New speed = 120% of x = 6x/5 km/hr Distance = 459 km According to the question 459/x – 459/(6x/5) = 90/60 459 x [(6 – 5)/6x] = 3/2 Therefore, x = 459 x (1/6) x (2/3) = 51 km/hr.
If 'A' = (2/5) of 'B', 'B' = (3/4) of 'C', then find the value of (A + B) :(B + C) .
Some amount was divided among A, B and C in the ratio 3:5:8. If the share of A is 40 less than share of C, then find the 1/4th of total amount (in Rs).
A quantity m is directly proportional to another quantity n. When m = 75, then n = 45. When n = 60, then find the value of m.
Ratio between two numbers is 6:11 and their difference is 50. Find the sum of the given two numbers.
If 30% of a certain number is equal to 4/5th of another number, what is the ratio between the numbers?
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