Question
If a person walks 20% more than of his usual speed,
reaches his distance 90 minutes before. If the destination is 459 km away, then the usual speed of a person is (in km/hr)?Solution
Let the usual speed be x km/hr New speed = 120% of x = 6x/5 km/hr Distance = 459 km According to the question 459/x – 459/(6x/5) = 90/60 459 x [(6 – 5)/6x] = 3/2 Therefore, x = 459 x (1/6) x (2/3) = 51 km/hr.
A body is said to be in equilibrium when:
Which polymer is used in the production of bullet-proof materials?
Which one among the following statements is not true for Mammals?
Which of the following is a chemical change?
Which vitamin is also known as Vitamin-B2?
If the root mean square speed of gas molecules is doubled, the absolute temperature of the gas:
Which vitamin helps in improving night vision?
Which vitamin is essential for RBC formation?
Which of the following statements for the given chemical reaction is true?
Fe₂ O₃ + 2Al → Al₂ O₃  + 2Fe
The force which opposes the relative motion between different layers of liquid or gases is called –
