Question
Abhinav improved his average travel speed by 8 km/h
after journeying for 5 hours, completing his trip in a total of 8 hours. If instead he had boosted his speed by 18 km/h after the initial 5 hours, he would have arrived at his destination 30 minutes earlier. Calculate the distance Abhinav covered during the portion of his trip with the increased speed.Solution
Let, the distance travelled by after 5 hours = ‘y’ km So, y/ (7.5 – 5) – y/ (8 – 5) = 18 – 8 y/2.5 – y/3 = 10 0.5y = 75 y = 150 So, distance travelled by Abhinav after travelling for five hours = 150 km
In the figure BD = CD = AC, ∠ABC = 27 ° , ∠ACD = y. Find value of x.
In an obtuse angle  triangle PQR, the external angle bisector of angle P intersect the extended part of line RQ at M and the external angle bisector...
The lengths of three medians in a triangles are 9 cm, 12 cm, 15 cm. What is the area of that traingle (in cm 2 )?
If G is the centroid and AD, BE, CF are three medians of ∆ABC with area 54 cm 2 , then the area of ∆BGD is?
The length of the each side of an equilateral triangle is 14√3. The area of incircle, (cm 2 ) is
The perimeter of a rectangle is 48 cm, and the ratio of its length to breadth is 3:5. What is the area of the rectangle?
Find area of a sector of radius 14 cm with central angle 90°. (π = 22/7)
From an external point P, two tangents PR and PS are drawn to a circle with a radius of 10 cm. If the length of each tangent is 14 cm, determine the per...
If in a ΔABC, D is a point on BC such that BD = 1cm , BC = 3 cm then what is ratio of area of ΔABD to area of ΔADC ?
Relevant for Exams:
