Question
Abhinav improved his average travel speed by 8 km/h
after journeying for 5 hours, completing his trip in a total of 8 hours. If instead he had boosted his speed by 18 km/h after the initial 5 hours, he would have arrived at his destination 30 minutes earlier. Calculate the distance Abhinav covered during the portion of his trip with the increased speed.Solution
Let, the distance travelled by after 5 hours = βyβ km So, y/ (7.5 β 5) β y/ (8 β 5) = 18 β 8 y/2.5 β y/3 = 10 0.5y = 75 y = 150Β So, distance travelled by Abhinav after travelling for five hours = 150 km
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