Question
A cheetah can catch a deer running with a speed of 90
km/h and is 75 meters ahead of it, in 15 seconds. Find the time taken by the cheetah to catch a zebra that is 160 metres ahead of it and is running with a speed which is 80% of that of the deer.Solution
Speed of the deer = 90 km/h = 90 × (5/18) = 25 m/s Distance covered by the cheetah in 15 seconds = 75 metres + distance covered by the deer in 15 seconds = 75 + 25 × 15 = 75 + 375 = 450 metres So, speed of the cheetah = 450/15 = 30 m/s Speed of the zebra = 25 × (80/100) = 20 m/s So, relative speed of the cheetah with respect to the zebra = 30 – 20 = 10 m/s Hence, time taken by the cheetah to catch the zebra = 160/10 = 16 seconds
(20% of 15% of 600 – 6) × 5 + 84 = ?2Â
180 ÷ 3 of 2 = 102 – ?
The sum of two numbers is 16 and their product is 63. The sum of their reciprocal is equal to:
∛21952 × 44 = ? × 14
What will come in the place of question mark (?) in the given expression?
(√1089 + 84 ÷ 2) % of 348 = 416 - ?
What will come in the place of question mark (?) in the given expression?
{(16 × 25) ÷ 32} × 12 = ? – 200
- What will come in place of (?) in the given expression.
(18 × 2) + (72 ÷ 3) – 16 = ? 13 X √? + 256 ÷ 4 = 30% of 900 - 50
1365 ÷ 15 + (? ÷ 5) = 62 × 3.5
Relevant for Exams:
