Question
A train travelling at the speed of 72 km/hr crosses
another train, having 60 meters less length and travelling in opposite direction at the speed of 54 km/hr in 6 seconds. If the longer train crosses a platform in 18 seconds, then the shorter train will cross the same platform in how many seconds?Solution
Speed of longer train = 72 × (5/18) = 20 m/s
Speed of shorter train = 54 × (5/18) = 15 m/s
Let length of longer and shorter trains be ‘L’ meters and (L – 60) metres, respectively.
According to question,
L + L – 60 = (20 + 15) × 6 = 210
2L – 60 = 210
L = 135 metres
So, L – 60 = 75 metres
Let length of platform is ‘P’ metres
So, P + 135 = 20 × 18 = 360
P = 360 – 135 = 225 meters
Desired time = (225 + 75)/15 = 300/15 = 20 seconds
8 9 30 155 ? 9837 108218
...23 48 98 198 ? 798
...3720 3842 ? 4092 4220 4350
The question below is based on the given series I. The series I satisfy a certain pattern, follow the same pattern in series II and answer the questions...
73920, 9240, ?, 220, 44, 11
20, 30, 40, 55, ?, 160
1600, 330, 48, 23.2, ?, 31.0464
100 180 294 448 648 ?
11 33 66 112 173 ? .
5 10 30 150 950 11550
...